‘First time in 20 years’ Alexander Zverev will be fighting for ATP #1 with Daniil Medvedev and Novak Djokovic at Monte Carlo
Novak Djokovic, Alexander Zverev and Daniil Medvedev
As the race for the Miami Open crown continues, Alexander Zverev defeated Thanasi Kokkinakis in straight sets, 6-4, 6-4, in a heavily hyped fourth-round encounter.
This year, Zverev has been the target of a lot of criticism. His tantrum in Acapulco was a shocking show of poor behaviour, but the world no. 3 appears to have regained his composure as he prepares to face Casper Ruud in the Miami Open quarterfinals. Nevertheless, now, under the current circumstances, analysis indicates that the 24-year-old has a strong chance to claim the World No.1 ranking at Monte Carlo Masters.
How will Alexander Zverev take a step forward towards the World No.1 ranking?
Under the present situation, the German stands a good chance of finishing first in the ATP rankings. At the Australian Open earlier this year, he had the same opportunity. But, following a drab fourth-round match in Melbourne against Dennis Shapovalov, he lost the golden chance. If Zverev wins the title in Miami, he will be only 400 points behind the World No. 1 in the world rankings. However, only if Daniil Medvedev falls in the Miami quarterfinals, this will happen.
It will also be a historic moment in tennis since, for the first time in nearly two decades, numerous players will be vying for the top spot at the Monte Carlo Masters. As Novak Djokovic, Daniil Medvedev, and Alexander Zverev will all be vying for the same prize at the same time, tennis fans should expect a thrilling showdown.
Alexander Zverev will lock horns with Casper Rudd in the quarterfinals of the Miami Open 2022
Casper Ruud, the World No.8, will meet German Alexander Zverev in the quarter-finals of the Miami tennis event. The boys faced off twice, with the German representative winning both occasions in two sets. Furthermore, logic dictates that the German is the overwhelming favourite in the upcoming match.
Pritha Ghosh
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